TypeError: 'in ' requires string as left operand, not NoneTypeįull error for the if statement: print(parser(lista_aziende_raw))įile "/home/enrico/Documents/Learning_Python/edo/web_scraper. The full error for the list comprehension: File "/home/enrico/Documents/Learning_Python/edo/web_scraper.py", line 41, in lista_aziende_raw = ĮDIT: Here the output of print(lista_aziende_raw).
I also tried to put it in an if statement, following this answer but that spits out TypeError: argument of type 'NoneType' is not iterable'. Lista_aziende_raw.append(link.get('href')) Is there a way to get what I want using list comprehension, or should I just use the re module? lista_aziende_raw =
#Python filter list stack overflow generator
I made them into generator comprehensions, so they are more memory efficient on their own (even though here I cast them to lists, as soon as I want to use them). I guess that in only looks for identical results, hence no results. I would make this two different functions, one for filtering all names of length n and one for all names starting with some letter. I know for a fact that names that contain Azienda are present in the list, but I get an empty list. This approach uses the built-in filter function and a lambda function to filter the elements from the list. 0.0001483900 Empirical Analysis of the Stack Overflow Tags Network 275.
Approach 3: Using the filter function and a lambda function. tags with the highest betweenness centrality is in the top 100 frequency list. I'm a beginner, I want to filter the list lista_aziende_raw. A filter operation on the array is also possible, where you test the size of the. Time Complexity: O(n) where n is the number of elements in the list Auxiliary Space: O(n), where n is the number of elements in the new output list.
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